How to represent root 3.5on number line
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Representation of √3 .5 on the real number line:
Steps involved:
(i) Draw a line and mark A on it.
SEE THE IMAGE !!!!
(ii) Mark a point B on the line drawn in step - (i) such that AB = 3. 5 units
(iii) Mark a point C on AB produced such that BC = 1unit
(iv) Find mid-point of AC. Let the midpoint be O
=> AC = AB + BC = 3.5 + 1 = 4.5
=> AO = OC = AC/2 = 4.5/2 = 2.25
(v) Taking O as the center and OC = OA as radius drawn a semi-circle. Also draw a line passing through B perpendicular to OB. Suppose it cuts the semi-circle at D. Consider triangle OBD, it is right angled at B.
(vi) Taking B as the center and BD as radius draw an arc cutting OC produced at E. point E so obtained represents √3. 5 as BD = BE =√3.5 radius Thus, E represents the required point on the real number line.
HOPE IT HELPED:)
Steps involved:
(i) Draw a line and mark A on it.
SEE THE IMAGE !!!!
(ii) Mark a point B on the line drawn in step - (i) such that AB = 3. 5 units
(iii) Mark a point C on AB produced such that BC = 1unit
(iv) Find mid-point of AC. Let the midpoint be O
=> AC = AB + BC = 3.5 + 1 = 4.5
=> AO = OC = AC/2 = 4.5/2 = 2.25
(v) Taking O as the center and OC = OA as radius drawn a semi-circle. Also draw a line passing through B perpendicular to OB. Suppose it cuts the semi-circle at D. Consider triangle OBD, it is right angled at B.
(vi) Taking B as the center and BD as radius draw an arc cutting OC produced at E. point E so obtained represents √3. 5 as BD = BE =√3.5 radius Thus, E represents the required point on the real number line.
HOPE IT HELPED:)
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