How to represent root 5.6 on a number line?
Answers
Answered by
77
hloo dear
To locate √5.6 on the number line, we have to follow the steps given below.
(1) Draw a line AB = 5.6 units and BC = 1 unit.
(2) Find the mid-point of AC and mark it as O. Taking O as the centre and OA as the radius, draw a semi-circle.
(3) From B, draw a perpendicular to AC. Let it meet the semi-circle at D. Taking B as the centre and BD as the radius, draw an arc that intersects the line at E.
Now, the distance BE on the line is √5.6 units
To locate √5.6 on the number line, we have to follow the steps given below.
(1) Draw a line AB = 5.6 units and BC = 1 unit.
(2) Find the mid-point of AC and mark it as O. Taking O as the centre and OA as the radius, draw a semi-circle.
(3) From B, draw a perpendicular to AC. Let it meet the semi-circle at D. Taking B as the centre and BD as the radius, draw an arc that intersects the line at E.
Now, the distance BE on the line is √5.6 units
Answered by
83
here is ur ans
Draw a line segment 5.6 cm .
name them A and B
The line A and B extend to C such that C= 1 cm
Now find midpoint O of line AC
now O as centre and OA as radius draw semicircle on B
now draw a line from B
now B as centre and BD as radius draw semicircle on E
thus BD= BE = √5.6
Draw a line segment 5.6 cm .
name them A and B
The line A and B extend to C such that C= 1 cm
Now find midpoint O of line AC
now O as centre and OA as radius draw semicircle on B
now draw a line from B
now B as centre and BD as radius draw semicircle on E
thus BD= BE = √5.6
nancy281:
pls mark as brainleast
Similar questions