Math, asked by devisapkota124, 10 months ago

How to simplify ( x+2)-1/x+2=5

Answers

Answered by Mihir1001
32

------------------------------------------------------------------------------------------------------------------------------------------¯\_(ツ)_/¯

<font color="blue" size="5px"><b>Answer:</b></font>

-------------------------------------------------------------------------------------------------------------------------------------------@_@

\huge\boxed{\fcolorbox{red}{#ffdfff}{answer}}

---------------------------------------------------------------------------------------------------------------------------------------------(´∇`*)

<font color="red" size="5px"><b>Step-by-step-explaination:</b></font>

--------------------------------------------------------------------------------------------------------------------------------------------------●_●

We have,

(x + 2) -  \frac{1}{x + 2}  = 5

 \implies  \frac{(x + 2)(x + 2) - 1}{x + 2}  = 5

 \implies  \frac{ {(x + 2)}^{2}  - 1}{1}  = 5 \times (x + 2)

 \implies  {x}^{2}  + 4x + 4 - 1 = 5(x + 2)

 \implies  {x}^{2}  + 4x + 3 = 5x + 10

 \implies  {x}^{2}  - 5x + 4x - 10 + 3 = 0

 \implies  {x}^{2}  - x - 7 = 0

This equation is of the form \bold{a {x}^{2}  + bx + c = 0},

where, a = 1 , b = - 1 and c = - 7

Now,

Discriminant,

D =  {b}^{2}  - 4ac

 \implies D =  {( - 1)}^{2}  - 4(1)( - 7)

 \implies D = 1 + 28

 \implies D = 29

Thus, D > 0

Then, the roots are real and unequal.

Henceforth,

x =  \frac{ - b -  \sqrt{D} }{2a}  =  \frac{ - ( - 1) -  \sqrt{29} }{2(1)}  =  \frac{1 -  \sqrt{29} }{2}

or,

x =  \frac{ - b +  \sqrt{D} }{2a}  =  \frac{ - ( - 1) +  \sqrt{29} }{2(1)}  =  \frac{1 +  \sqrt{29} }{2}

Hence,

\huge\bold{x =  \frac{1 -  \sqrt{29} }{2} } or \huge\bold{x =  \frac{1 +  \sqrt{29} }{2} }

----------------------------------------------------------------------------------------------------------------------------------------づ ̄ ³ ̄)づ

{\fcolorbox{green}{#82ffff}{\textcolor{#300061}{your required answer is above ......... keep smiling ….. :)}}}<marquee direction="down" scrollamount="1/10">❤just love❤</marquee><marquee direction="up" scrollamount="1/10">❤just love❤</marquee>

.

.

.

.

.

.

.

\bold{hope.... \: it \: helps.}

and... mark this answer as ❤BRAINLIEST❤

and... if u can...... then

<p style="background-color:gold;"><b><i>......<u>..follow me..</u>...... !!</i>!</b></p>

Thanks for reading................................................ :)

\huge{\fcolorbox{red}{orange}{brainliest \: answer}}

<body style="background-color:rgb(255,245,125); back">  .........<b>………..❤Thank you to all my lovely readers❤............╭∩╮(︶︿︶)╭∩╮..</b>..</body>

<marquee> please answer my questions too… ….. …please¯\_(ツ)_/¯</marquee>

<marquee direction="right"> ( ˘ ³˘)❤ </marquee>

<marquee bgcolor="pink" behaviour="slide" direction="down" scrollamount="2" height="60px" width=120px">❤thanks❤ ... </marquee><marquee bgcolor="pink" behaviour="slide" direction="up" scrollamount="2" height="60px" width="200px">......... to........ my answer</marquee><marquee behaviour="slide" direction="left" scrollamount="5" height="60px" width="400px">30 thanks❤ = follow<br/>40 thanks❤ = get my no. in inbox<br/>50 thanks❤ = as u wish...</marquee>

Similar questions