Question

How to slove area of trapezium with using heron's formula?

Answer 1

Answer: A = sqrt[S(S-a)(S-b)(S-c)]

An example is given below....

Step-by-step explanation:

Let the trapezium be ABCD so that AB = 10 m , BC = 13 m , CD = 25 m and DA = 14 m. Here AB and CD are parallel sides of trapezium.

Draw a line from B to CD which is parallel to DA. The line meets at E on CD.

BE = DA = 14 m.

CD = CE + ED

25 = CE + 10

CE = 15 m.

Therefore BCE forms a triangle. Use Heron's formula to find the area of this triangle.

Heron's formula A = sqrt[S(S-a)(S-b)(S-c)]

Find height h from this area. [h = 2A/b , here b = BE]

Area of trapezium = 1/2(AB + CD)h.

This may help you........

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Thank you..........

Answer 2

Answer:

divide it into 2 triangles and one square/rectangle