how to solve 1 part of 4th question
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multiply 2 in NaNO3 and multilpy 2 in NaNO2
anuj02222:
multiply by 2 in NaNO3 and multiply by 2 NaNO2
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NA=1
NO=3
products
NA=1
NO=2
O=2
THEN
EQUATION WILL BE
3NANO3 GIVES 3NANO2+O2
NO=3
products
NA=1
NO=2
O=2
THEN
EQUATION WILL BE
3NANO3 GIVES 3NANO2+O2
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