Question

How to solve 12(2x-3y)^2-16(3y-2x)

Answer 1

12(2x-3y)^2-16(3y-2x)
=12(3y-2x)^2-16(3y-2x)
=4(3y-2x) [3(3y-2x)-4]
=4(3y-2x) (9y-6x-4)

Answer 2

Solution ●●●●
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$= 12 {(2x - 3y)}^{2} + 16(2x - 3y)$

$= (2x - 3y) \: [\: 12(2x - 3y) + 16]$

$= (2x - 3y)(24x - 36y + 16)$

$= (2x - 3y) \: 4(6x - 9y + 4)$

$= 4(2x - 3y)(6x - 9y + 4)$
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