Question

How to solve 15th question

Answer 1

Answer:

Step-by-step explanation:

BRAINLIEST BRAINLIEST BRAINLIEST

Answer 2

$(\dfrac{x+1}{x-4})^{2}=\dfrac{x+8}{x-2}\\ \\ \\ \\ \dfrac{x^2 +1+2x}{x^2+16-8x}=\dfrac{x+8}{x-2}\\ \\ \\ \\(x^2 +1+2x)(x-2)=(x^2+16-8x)(x+8)\\ \\ \\ \\x^3+x+2x^2- 2x^2 -2 -4x=x^3+16x-8x^2+8x^2+128-64x\\ \\ \\ \\x-4x-2=16x-64x+128\\ \\ \\ \\16x-x=64x-4x-128-2\\ \\ \\ \\15x=60x-130\\ \\ \\ \\60x-15x=130\\ \\ \\ \\45x=130\\ \\ \\ \\x=\dfrac{130}{45}\\ \\ \\ \\x=\dfrac{26}{9}$

Hence,

$\boxed{\red{\bold{\sf{\dfrac{26}{9}}}}}$

$\rule{200}{2}$

Things to remeber:-

$(a+b)^2=a^2+b^2+2ab$

$(a-b)^2=a^2+b^2-2ab$

Other things to look for:-

[1]Multiplication of binomial and a trinomial

[2]cancellation of like terms with variables