How to solve 2 digit numbers which when added to 27 get reversed?
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let unit digit be x
tens digit =15-x
no = 10 (15-x)+x
150-10x+x
1500--9x
reversed no . = 10× (x)+15-x
10x+15-x = 9x+15
27 is added to the no.
150-9x+27 = 9x+15
177-9x =9x+15
177-15 = 9x+9x
162 = 18x
x = 162/18
x = 9
unit digit = 9
tens = 15-9 = 6
no = 150-9×9
150-81 =69
tens digit =15-x
no = 10 (15-x)+x
150-10x+x
1500--9x
reversed no . = 10× (x)+15-x
10x+15-x = 9x+15
27 is added to the no.
150-9x+27 = 9x+15
177-9x =9x+15
177-15 = 9x+9x
162 = 18x
x = 162/18
x = 9
unit digit = 9
tens = 15-9 = 6
no = 150-9×9
150-81 =69
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