how to solve (2a+b)3-(2a-b)3
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Thank you
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(2a+b)³ - (2a-b)³ = 2b³ + 24a²b
Given:
(2a+b)³ - (2a-b)³
To find:
Solve given expression
Solution:
Formula used:
(a + b)³ = a³ + b³ + 3a²b + 3ab²
(a - b)³ = a³ - b³ - 3a²b + 3ab²
Given (2a+b)³ - (2a-b)³
By using the above formula,
=> (2a)³ + (b)³ + 3(2a)²(b) + 3(2a)(b)² - [ (2a)³ - (b)³ - 3(2a)²(b) + 3(2a)(b)² ]
=> 8a³ + b³ + 12a²b + 6ab² - [ 8a³ - b³ - 12a²b + 6ab² ]
=> 8a³ + b³ + 12a²b + 6ab² - 8a³ + b³ + 12a²b - 6ab² ]
=> b³ + 12a²b + b³ + 12a²b
=> 2b³ + 24a²b
Therefore,
(2a+b)³ - (2a-b)³ = 2b³ + 24a²b
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