how to solve (3x-1)^2-(3x-2)(3x+1)
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sintu55:
bhai your answer is wrong
its coming 3-3x
answer
Bhai just go through the solution once again
check if you’ve made any + - mistakes
bhai can i get your no
i have check my question its correct
Yes sure 8179710107
send me the question
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=(3x-1)^2-(3x-2)(3x+1)
=[(3x)^2+1^2-2×3x×1] -[ 3x(3x+1) -2(3x+1)]
=(9x^2+1 -6x)-[(9x^2+3x)-(6x+2)]
=9x^2+1-6x-(9x^2+3x-6x-2)
=9x^2+1-6x-9x^2-3x+6x+2
=3-3x
=3(1-x)
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