Question

Two balls are dropped from the same point after an interval of 1s. if acceleration due to gravity is 10 m/s2 , what will be their separation 3 seconds after the release of first ball ? (a) 5 m (b) 10 m (c) 25 m (d) 30 m​

Answer 1

answer is 25 ....I hope this help you

Answer 2

Answer:

The separation between the balls is 25m i.e.option(c).

Explanation:

Distance travelled by the first ball in 3 seconds,

$S_1=\frac{1}{2}gt^2$                 (1)

Where,

g=acceleration due to gravity=10m/s²

By putting the values in equation (1) we get;

$S_1=\frac{1}{2}\times 10\times (3)^2=5\times 9=45m$      (2)

Distance traveled by the second ball,

$S_2=\frac{1}{2}gt^2$        (3)

By putting the values in equation (3) we get;

$S_2=\frac{1}{2}\times 10\times (2)^2=5\times 4=20m$        (3)    

We have taken t=2sec as the balls are dropped after an interval of 1si.e.

t=3-1=2s

Distance between the balls 3 seconds after the release of the first ball,

$D=S_1-S_2$        (4)

By substituting the value of S₁ and S₂ in equation (4) we get;

$D=45-20=25m$

Hence, the separation between the balls  3 seconds after the release of the first ball is 25m i.e.option(c).