Question

how to solve 8x+4=3(x-1)+7 ?????

Answer 1

On solving, $\bold{8x + 4 = 3(x - 1) + 7 = 0}$

Step-by-step explanation:

The given problem is the polynomial of degree 1.

$8x + 4 = 3(x - 1) + 7$

$8x + 4 = 3x - 3 + 7 = 3x + 4$

On bring the variables one side and constants another side, we get,

$8x - 3x = 4 - 4$

$5x = 0$

On solving, we get,

$x = 0$

Answer 2

Answer:

$x = 0$

Step-by-step explanation:

$Given \: simple \: equation:\\ 8x+4=3(x-1)+7$

$\implies 8x+4=3x-3+7$

$\implies 8x+4=3x+4$

Subtract 4 both sides of the equation, we get

$\implies 8x+4-4=3x+4-4$

$\implies 8x=3x$

$\implies 8x-3x=0$

$\implies 5x = 0$

$\implies x = 0$

Therefore,

$x = 0$

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