Question

how to solve 8x+4=3(x-1)+7 ????? Plus the check aslo

Answer 1

Let's solve your equation step-by-step.
8x+4=3(x−1)+7
Step 1: Simplify both sides of the equation.
8x+4=3(x−1)+7
8x+4=(3)(x)+(3)(−1)+7(Distribute)
8x+4=3x+−3+7
8x+4=(3x)+(−3+7)(Combine Like Terms)
8x+4=3x+4
8x+4=3x+4
Step 2: Subtract 3x from both sides.
8x+4−3x=3x+4−3x
5x+4=4
Step 3: Subtract 4 from both sides.
5x+4−4=4−4
5x=0
Step 4: Divide both sides by 5.
5x5=05
x=0

Verification:
Put x=0 in the original equation.
8(0)+4=3(0-1)+7
4=4
L.H.S=R.H.S
Hence, proven.

© Hades09

Answer 2

We solve the above equation by Transposition. 8x + 4 = 3 ( x - 1 ) + 7
8x + 4 = 3x - 3 + 7
8x + 4 = 3x + 4
8x + 4 - 4 = 3x
8x - 5x = 0
3x = 0 .
x = 0 .

Check :
8(0) + 4 = 3 ( 0 - 1 ) + 7
4 = -3 + 7
4 = 4 .

Hope helped!