Question

How to solve 9a^2-b^2+4b-4

Answer 1

hey mate this is your answer:
firstly take α and β as is zeroes we know α×β =c /a , further u can find an equation formed u should have to find its zeroes put these zeroes instead of b and get your desired answer

Answer 2

Solution ●●●●
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$= {9a}^{2} - ( {b}^{2} - 4b + 4)$

$= ( {3a})^{2} - ( {b}^{2} - 2.b.2 + {2}^{2} )$

$= ( {3a})^{2} - ( {b - 2})^{2}$

$= (3a + b - 2)[3a - (b - 2)]$

$= (3a + b - 2)(3a - b + 2)$
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I hope it will help you
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