how to solve (a+b)(c-d) +(a-b)(c+d)+2(ac+bd)
Answers
Step-by-step explanation:
Given:
a(x+y) + b(x-y) = a² - ab + b² ..(i).,
a(x+y) - b(x-y) = a² + ab - b² ...(ii)
_____________________________________________________________
To find,
The values of x and y.
Adding both the equations,
We get,
=> a(x + y) + b(x - y) + a(x + y) - b(x - y) = a² - ab + b² + a² +ab - b²
=> 2a(x + y) = 2a²
=> x + y = a ...(iii),
____________________
Subtracting (ii) from (i),
=> a(x + y) + b(x - y) -(a(x + y) - b(x - y)) = a² - ab + b² - (a² + ab -b²)
=> a(x + y) + b(x - y) - a(x - y) + b(x - y) = a² - ab + b² - a² - ab + b²
=> 2b(x - y) = -2ab + 2b²
=> 2b(x - y) = 2b² - 2ab
=> 2b(x - y) = 2b(b - a)
=> x - y = b - a ..(iv)
_______________________
Adding (iii) & (iv),
We get,
=> (x + y) + (x - y) a + b- a
=> 2x = b
=> x = b/2
substitute value of x in (iv)
y= a - b/2
Pls mark me as brainlist
Answer:
how to solve (a+b)(c-d) +(a-b)(c+d)+2(ac+bd)