Math, asked by thenameissilvia8, 5 hours ago

How to solve
(a8+a4b4+b8) by (a2+b2-ab)

Answers

Answered by cjha33976

1

Answer:

a8 - b8 = ((a4)2 - (b4)2) [the difference of two squares]

= (a4 + b4)(a4 - b4)

= (a4 + b4)(a2 + b2)(a2 - b2)

= (a4 + b4)(a2 + b2)(a + b)(a -b

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