Question

how to solve and get answer

Answer 1

Diagonal divide rectangle in two equal triangle

area of rectangle = 2 area of triangle

area = 2X1/2XbaseXheight
BASE= 10 cm (diagonal of rectangle)
height = 5 cm (diagonal divide in two equal parts that is 5 cm)

2X1/2XbaseXheight
5X10
= 50 cmsq

Area of rectangle = LXB
50=LXB
50=8B (length of rectangle given)
B= 50/8cm

So perimeter of rectangle = 2 (L+B)
= 2 (8+50/8)
=2 (8+6.25)
= 2 (14.25) cm
=28.5cm

So perimeter of rectangle is 28.5 cm

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