Question

how to solve any under root quadratic eq
$\sqrt5x + 7x + 2 \sqrt{5}$

Answer 1

Answer :

Now, √5x² + 7x + 2√5

= √5x² + 5x + 2x + 2√5

= √5x (x + √5) + 2 (x + √5)

= (x + √5) (√5x + 2),

which is the required factorization.

Thus, the zeroes of the given polynomial are

(- √5) and (- 2/√5).

#MarkAsBrainliest

Answer 2

Your question needs a correction,

Correct question : √5x² + 7x + 2√5

=> √5x² + (5 + 2)x + 2√5

=> √5x² + 5x + 2x + 2√5

=> √5x(x + √5) + 2(x + √5)

=> (√5x + 2) (x + √5)

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If your question is correct, according to your question,

√5x + 7x + 2√5

=> x(√5 + 7) + 2√5

=> x(2.24 + 7) + 2(2.24)

=> 9.24x + 4.48


I hope this will help you


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