how to solve bracket bodmas using fraction
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Answer:
B- Brackets
O- Order
D- Division
M- Multiplication
A- Addition
S- Subtraction
Using this formula, we can solve any sum.
For ex:- [25-{10+(1+19)-2}+7]
[25-{10+20-2}+7]
[25-28+7]
[-3+7]
4 Ans
Note:- We will first evaluate the smallest bracket and then keep on increasing the number of operations as per the brackets.
Hope it helps.
Please mark my answer as BRAINLIEST.
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