Math, asked by AmV, 1 year ago

How to solve complex numbers using geometry?

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Answered by Anonymous
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Complex Numbers and Geometry

Several features of complex numbers make them extremely useful in plane geometry. For example, the simplest way to express a spiral similarity in algebraic terms is by means of multiplication by a complex number. A spiral similarity with center at c, coefficient of dilation r and angle of rotation t is given by a simple formula

f(z) = r(z - c)(cos(t) + i·sin(t)) + c.

Circle

A particularly simple equation is that of a circle:

{z: |z - a| = r},

is the circle with radius r and center a. By squaring that equation we obtain

(z - a)(z' - a') = r²

or

zz' - (za' + z'a) + (aa' - r²) = 0.

and finally

zz' - (za' + z'a) + s = 0,

where s is a real number. The circle is centered at a and has the radius r = √aa' - s, provided the root is real.

This representation of the circle is more convenient in some respects. For example, we may immediately check that the transformation w = f(z) = 1/z maps circles onto circles. Indeed, substituting z = 1/w we get

1/w × 1/w' - (a'/w + a/w') + s = 0

which, if multiplied by ww', leads to

ww' - (wb' + w'b) + t = 0,

where b = a'/s and t = 1/s, an equation in the same form.

Letting a = α + iβ yields yet another form of essentially same equation:

zz' - α(z + z') - iβ(z - z') + s = 0,

where α and β are both real. Yet the most general form of the equation is this

Azz' + Bz + Cz' + D = 0,

which represents a circle if A and D are both real, whilst B and C are complex and conjugate. For A = 0, the equation represents a straight line.

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