how to solve cos(sin-1 x)=1/6
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Can be solved in this way
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Hi
let sin^-1x =alpha
then, sin alpha= x
therefore, cos(sin^-1 x) =1/6
or, cos(alpha) =1/6 [sin^-1 x= alpha]
or, alpha= 0.99
let sin^-1x =alpha
then, sin alpha= x
therefore, cos(sin^-1 x) =1/6
or, cos(alpha) =1/6 [sin^-1 x= alpha]
or, alpha= 0.99
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