Question

How to solve if there is square root in a square root?

Answer 1

Answer:

How do you solve equations with square roots?

To Solve a Radical Equation:

• Isolate the radical on one side of the equation.
• Square both sides of the equation.
• Solve the new equation.
• Check the answer. Some solutions obtained may not work in the original equation.

What cancels out a square root?

That inverse relationship between squaring numbers and square roots is important, because in plain English it means that one operation undoes the effects of the other. That means that if you have an equation with square roots in it, you can use the "squaring" operation, or exponents, to remove the square roots.

Step-by-step explanation:

#Hope you have satisfied with this answer.

Answer 2

Answer:

How do you take the square root of some number?

I think what you meant is, how to find the square of a number easily without multiplying it by itself, which is obvious and often laborious. Here are some tricks. Neither of these will work for all cases: You need to use the method more appropriate for the case.

1) Useful when the number is close to a number with which you can do multiplication easily (like 100):

Use the identity: a2−b2=(a+b)(a−b)

So, a2=(a+b)(a−b)+b2

Find a number b so that either a+b or a−b is an easy number to multiply.

For example, 982=(98+2)(98−2)+22=9604 .

Or, 1032=(103+3)(103−3)+32=10609 .

As a special case, if the number is halfway between two easy numbers, as in:

352=40⋅30+52=1225 . This trick can be used for all two-digit numbers ending in 5. Multiply the first digit k with (k+1) and then add 25 in the end. For example, 752=5625 because 7⋅8=56 .

2) Use the identity (a±b)2=a2±2ab+b2 . Find two numbers a and b so that the required number is (a±b) and both a and b can be easily multiplied and squared.

Taking the same examples, 982=(100−2)2=1002−400+4=9604 and 1032=(100+3)2=10000+600+9=10609 .

There are other similar tricks also. However, please bear in mind that multiplying the number by itself is the fastest method that works for all numbers.

Step-by-step explanation:

#Hope you have satisfied with this answer.