Question

how to solve it???? 23^0 + 4^-1 × 2^3​

Answer 1

Step-by-step explanation:

$= {23}^{0} + {4}^{ - 1} \times {2}^{3}$

$= 1 +( {2}^{2}) {}^{ - 1} \times {2}^{3}$

$= 1 + {2}^{( - 2 + 3)}$

$= 1 + 2 \\ = 3$