how to solve it can anyone tell me plz
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since two resistance are parallel
1/Rp= (1/3 +1/6 )
Rp= 2ohm
Now other three are in paralllel
1/Rp = 1/3 +1/6+1/2
1/Rp= 6/6ohm=1ohm
Rp= 1ohm
Now above two are in parallel so
Rs (eq)= 2+1=3ohm
total voltage = 12v
i = V/R=12/3=4A
since the 3 ohm and 6ohm are in paralllel so using current division rule
current in 3ohm is 4/3a and In 6 ohm is 8/3a
Now 4/3A is divided in 3 resistor so
current divided in ratio 3:2:1
so current in Ammeter is = 4A in downward
Now
current in Ammeter dur to 6ohm resistor= 2A upward
so reading of Ammeter is = 4 - 2 = 2A upward .
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