Question

how to solve it
for a reaction




N2+3H -----> 2NH3



the equilibrium mixture contains 0.25M nitrogen and 0.15M hydrogen gas at 25 degree centigrade calculate the concentration of NH3 given kc=9.6 The volume of container is 1dm^3

Answer 1

From the reaction, we can see that Kc= [NH3]²/[H2]³[N2],So using the concentrations and Kc value we can get that [NH3]²=[H2]³[N2]×Kc. So [NH3]²= 0.15²×0.25×9.6⇒[NH3]=0.23 M