How to solve it please help me.. this question is from inverse trigonometric functions chapter..
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cos(tan^-1 X) =cos(π/2- cot^-1 (3/4))
tan^-1x=π/2 - tan^-1 (4/3)
tan^-1 X + tan^-1 (4/3)=π/2
(x+4/3)/(1-4/3x)=infinity
therefore
1-(4/3)x=0
4/3x=1
x=3/4
tan^-1x=π/2 - tan^-1 (4/3)
tan^-1 X + tan^-1 (4/3)=π/2
(x+4/3)/(1-4/3x)=infinity
therefore
1-(4/3)x=0
4/3x=1
x=3/4
Vivekkr:
thnk u
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