Question

how to solve it using substitution method:
3x+2y+25=0
2x+y+10=0

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Answer 1

Answer:

Here is your answer......

Answer 2

Answer:

x=50 and y=-110

Step-by-step explanation:

3x+2y+25=0 (eq. 1)

2x+y+10=0 (eq. 2)

adding eq. 1 and eq. 2, we get;

5x+3y+35=0

=>5x=35-3y

=>x=35-3y

5

putting the value of x in eq. 1, we get-

3×(35-3y)+2y+25=0

5

=>(105-9y)+2y=-25

5

=>105-9y+10y=-25

5

=>105+y=-25

5

=>y=-5-105

=>y=-110

now put the value of y in eq. 2 we get

2x+(-110)+10=0

=>2x=-10+110

=>x=100

2

=>x=50