Math, asked by pranjal7, 11 months ago

How to solve log 0.020


Anonymous: got it or Not?

Answers

Answered by Anonymous
6

good \:  \: morning \:  \\  \\  \\ some \: formula \: of \: log \\  \\  \\ 1) \:  \:  \:  log(x {}^{n} )  = nlog(x) \\  \\2) \:  \:  \:   log(mn)  =  log(m)  +  log(n)  \\  \\ 0.020 = 2 \times 10 {}^{ - 2}  \\  \\  \\  log(2 \times 10 {}^{ - 2} )  \\  \\  \\  =  log(2)  +  log(10 {}^{ - 2} )  \\  \\  \\  \\  =  log(2)  - 2 log(10)  \\  \\  \\  =  log(2)  -2 \\  \\  \\  = 0.301 - 2 \\  \\  \\  =  - 1.69


pranjal7: Explain last step
Anonymous: log 10 is 1
Anonymous: and log 2 = 0.301
Anonymous: So, 0.301 - 2 = -1.69
pranjal7: How to solve log 1 ÷ 0.020
Anonymous: log ( 1 ) = 0
Anonymous: obviously log ( 1 ) / 0.0020 = 0
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