Math, asked by durgaprasaddasyam, 8 months ago

how to solve (p²-q²)²-4p²q²​

Answers

Answered by usharmavn
1

Answer:

Step-by-step explanation:

p4 + q4 - 6p2q2

Answered by ksonakshi70
4

Answer:

(p {}^{2}  - q {}^{2 } ) {}^{2}  - 4p {}^{2} q {}^{2}  \\  = (p { {}^{2} )}^{2}  + (q {}^{2} ) {}^{2}  - 2 \times p {}^{2}  \times q {}^{2}  - 4p {}^{2} q {}^{2}  \\  = p {}^{4}  + q {}^{4}  - 2p {}^{2} q {}^{2}  - 4p {}^{2} q {}^{2}  \\  = p {}^{4}  + q {}^{4}  - 6p {}^{4} q {}^{4}

using identity (a-b)^2 = a^2 +b^2-2×a×b

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