Question

How to solve : $sin^{2}$θ = 5/16

Answer 1

Step-by-step explanation:

${ \sin}^{2} \ θ+ { \cos }^{2} \ θ= 1$

$= > { \cos}^{2} θ = 1 - \frac{5}{16}$

=>cosθ=√11/4

=>sinθ=√5/4