How to solve the above question?
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In triangle ADC
_________________
Angle A = 60°
Angle C= 60°
Then also by Triangle sum property rule
we comes to know that angle D= 60°
___________________
Now we know that linear line makes an angle of 180°
so , 180°= angle ADC + angle ADB
180° = 60° + angle ADB
Angle ADB= 180°-60°= 120°
_______________________
By Triangle sum property rule,
In triangle ADB
angle A+ angleD + angle B= 180°
30°+ 120°+angleB = 180°
angle B = 30°
____________________
Thus angle ABD= angle BAD
The opposite sides are equal of this angle
side AD= side BD
Similarly side AC= AD= CD= 4cm
___________________
Thus side BC= BD+ DC
BC= 4cm + 4cm
BC= 8cm
_____________________
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In triangle ADC
_________________
Angle A = 60°
Angle C= 60°
Then also by Triangle sum property rule
we comes to know that angle D= 60°
___________________
Now we know that linear line makes an angle of 180°
so , 180°= angle ADC + angle ADB
180° = 60° + angle ADB
Angle ADB= 180°-60°= 120°
_______________________
By Triangle sum property rule,
In triangle ADB
angle A+ angleD + angle B= 180°
30°+ 120°+angleB = 180°
angle B = 30°
____________________
Thus angle ABD= angle BAD
The opposite sides are equal of this angle
side AD= side BD
Similarly side AC= AD= CD= 4cm
___________________
Thus side BC= BD+ DC
BC= 4cm + 4cm
BC= 8cm
_____________________
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