how to solve these types of ques
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faizaankhanpatp3bt9p:
x2 -( a + B)x + aB i
whats that
is the formula to solve the answer
eqn is already given
we will know what alpha + beta and alphabeta
Answers
Answered by
5
U can solve this type of questions like this
Let
a+β=4 aβ=3
=(3a+3β)=3*4=12
=3a*3β=9*3=27
If 3a,3β are zeros of the quadratic polynomial then the equation is
x^2-(3a+3β)x+9aβ=0then
x^2-12x+27=0
Let
a+β=4 aβ=3
=(3a+3β)=3*4=12
=3a*3β=9*3=27
If 3a,3β are zeros of the quadratic polynomial then the equation is
x^2-(3a+3β)x+9aβ=0then
x^2-12x+27=0
a + B = 3 and aB = -4
Answered by
1
x² - 3x - 4 = 0
therefore (a+B) = 3 and (aB) = -4
hence now we can substitute this in the question
first solve the last then the first
=> α²+β² = (α+β)² - 2αβ = 9+8 = 17
=> α²+β² / αβ = 17 / -4
=> (α²/β) + (β²/α) =(α+β)³ - α(αβ)+ β(αβ) / αβ
= 27 - 12 / -4 = -15 / 4
hope it helped sorry for the late answer
therefore (a+B) = 3 and (aB) = -4
hence now we can substitute this in the question
first solve the last then the first
=> α²+β² = (α+β)² - 2αβ = 9+8 = 17
=> α²+β² / αβ = 17 / -4
=> (α²/β) + (β²/α) =(α+β)³ - α(αβ)+ β(αβ) / αβ
= 27 - 12 / -4 = -15 / 4
hope it helped sorry for the late answer
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