How to solve this 4x^2+5√2x-3
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4x^2+ 6root2x - root2x - 3
2 root2x ( root2x + 3) -1 (root2x + 3)
(root2x + 3) (2 root2x - 1 ) = 0
( root2x × 3 ) =0 (2 root2x - 1) = 0
x = 3 root2 or x = 1/2 root2
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