Math, asked by harshnaveen8091, 1 year ago

how to solve this answer (999)^3

Answers

Answered by amanchakrawarty
1

(1000-1)³

• (a-b)³=a³-b³-3xy-(a-b)

= (1000)³-(1)³-3×1000×1 (1000-1)

= 1000000000-1-3000(1000-1)

= 1000000000-1-3000000+3000

= 997002999


confusinggirl: is it ryr?
confusinggirl: ryt
Answered by khantasmiyakhan
2

Answer:

(999)³=(1000-1)³

we know that,

(a-b)³=a³-b³-3a²b+3ab²

=(1000)³-(1)³-3.(1000)².1+3.1000.(1)²

=1000000000-1-3000000+3000

=1000003000-2999999

=997003001


confusinggirl: is it ryt
khantasmiyakhan: yesss whyy
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