How to solve this equation .0.5E+0.5=y------(1) 3y-6=E------(2). pls explain
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multiply eq1 with 2 u will get,
1E+1= 2y
E+6= 3y
(-)(-). (-)
0-5=-y
therefore y= 5
substitute value of y in eq 2
E+6=3(5)
E=15-6
E=9.
1E+1= 2y
E+6= 3y
(-)(-). (-)
0-5=-y
therefore y= 5
substitute value of y in eq 2
E+6=3(5)
E=15-6
E=9.
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