how to solve this equation??
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rawstar99:
by matrix
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Answered by
3
x+y=6
x=6-y. equation 1
xy=8
using equation 2
6y-y^2=8
bow y^2 -6y-8=0
solve this equation and get the answer
x=6-y. equation 1
xy=8
using equation 2
6y-y^2=8
bow y^2 -6y-8=0
solve this equation and get the answer
Answered by
3
Hi...☺
Here is your answer...✌
As Matrix are equal
Therefore, their corresponding elements must be equal
Comparing the corresponding elements
We get,
x+y = 6
x = 6-y ...(1)
And,
xy = 8
(6-y)y = 8 ...[ From (1) ]
6y-y² = 8
y²-6y+8 = 0
y²-4y-2y+8
y(y-4)-2(y-4) = 0
(y-2)(y-4) = 0
=> y = 2 or y = 4
Putting value of y in eq(1)
We get,
x = 4 or x = 2
And,
5+z = 5
z = 5-5
z = 0
HENCE,
x = 4 or 2
y = 2 or 4
z = 0
Here is your answer...✌
As Matrix are equal
Therefore, their corresponding elements must be equal
Comparing the corresponding elements
We get,
x+y = 6
x = 6-y ...(1)
And,
xy = 8
(6-y)y = 8 ...[ From (1) ]
6y-y² = 8
y²-6y+8 = 0
y²-4y-2y+8
y(y-4)-2(y-4) = 0
(y-2)(y-4) = 0
=> y = 2 or y = 4
Putting value of y in eq(1)
We get,
x = 4 or x = 2
And,
5+z = 5
z = 5-5
z = 0
HENCE,
x = 4 or 2
y = 2 or 4
z = 0
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