Math, asked by nived23, 1 year ago

how to solve this equation 5(2x-3)-3(3x-7)=5


BIRDHAN: break the bracket first
nived23: how to break the bracket please explain
seemabanwala1122: 10x-15-9x+21=5 , x+6=5 ,x=-1
jatinsoni5808: You can see the answer in description
BIRDHAN: 10x-15-9x+21=5... 10x-9x-15+21=5...x+6=5.....x=5-6....x=-1

Answers

Answered by dfgh4
320
 = > 5(2x - 3) - 3(3x - 7) = 5 \\ \\ = > 10x - 15 - 9x + 21 = 5 \\ \\ = >10x - 9x - 15 + 21 = 5 \\ \\ = > x + 6 = 5 \\ \\ = > x = 5 - 6 \\ \\ = > x = - 1 \\ \\ Here \: is \: your \: answer \\ \\ Very \: simple \: question
Answered by priyadarshinibhowal2
0

x = -1.

  • An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. A linear equation with one variable has the conventional form Ax + B = 0. In this case, the variables x and A are variables, while B is a constant. A linear equation with two variables has the conventional form Ax + By = C.
  • Each term in a linear equation has an exponent of 1, and when this algebraic equation is graphed, it always produces a straight line. It is called a "linear equation" for this reason.

Here, according to the given information, we are given that,

The equation is given as,

5(2x-3)-3(3x-7)=5.

Or, 10x-15-9x+21=5.

Or, x+6=5.

Or, x=5-6.

Or, x=-1.

Hence, x is -1.

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