Question

how to solve this???? Find the value of 'n'​

Answer 1

Answer:

${4}^{2n} \times 4 {}^{n} = {2}^{12} \\ {2}^{2 \times 2n} \times {2}^{2n} = {2}^{12} \\ {2}^{4n + 2n} = {2}^{12} \\ 6n = 12 \\ n = \frac{12}{6} = 2$