Question

how to solve this fraction

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Answer 1

Answer:

Solutions are in the attachment

Step-by-step explanation:

Take LCM and solve

hope it helps

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Answer 2

1)$\frac{11}{21}$ ,2)$\frac{42}{45}$,3)$\frac{11}{16}$,4)$\frac{-6}{28}$

Just applying LCM(Least common multiple) to the denominators making common and answer is found based on operator present at numerator

The explanations are:

1)LCM for 21 and 7 is 21

 $\frac{2*1}{21*1}+$$\frac{3*3}{7*3}$$=\frac{9+2}{21}$$=\frac{11}{21}$

2)LCM for 9 and 5 is 45

 $\frac{3*5}{9*5}+\frac{3*9}{5*9}=\frac{15+27}{45}=\frac{42}{45}$

3)LCM for 4 and 16 is 16

 $\frac{3*4}{4*4}-\frac{1*1}{16*1}=\frac{12-1}{16}=\frac{11}{16}$

4)LCM for 28 and 7 is 28

 $\frac{6*1}{28*1}-\frac{3*4}{7*4}=\frac{6-12}{28}=\frac{-6}{28}$