Question

how to solve this geometric progression question plz help​

Answer 1

$<marquee>let it go$.

$\color{blue}{kahe\:ko\:chahiye\:ye\:answer\:}$

$\color{purple}{q\:chahiye\:ye\:answer\: }$

$<color{blue}>let me awake$

Answer 2

Here first term.

a=/3

common ratio be

r=1/3

Finding the 15 term

n=a(r)^15-1

n=a(1/3)14

n=root(3)*

n=(/3)/(3)^14

Hope it helps you

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