Math, asked by Rabie, 1 year ago

how to solve this:-
It is a 5 mark question i am offering you with 48 points for this question
answer it in full steps
pls answer fast

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Rabie: please answer fast

Rabie: no body knows the ans

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Answered by Shreya01

This is the answer. Hope this help. Mark as brainliest if it's good.

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Shreya01: see picture is not opening, loading so I tell u the rest solution here

Shreya01: how to find exterior angle of triangle aep and pic, den see abcp is cyclc quad, den x+y+z+x=180,den x=52

Shreya01: z+y=90,from equation (2x+z+y=180),put value y+z=90, den x=45

Shreya01: sorry but picture is black when full screened.. so.. u do it this way u will get the ans, and u can get help from the part that can be seen

Rabie: thanks

Answered by maria9

Now
let EAP = a
PCB = a
[APCB is cyclic quadrilateral so exterior angle is equal to the interior opposite angle]

PCD = 180- PCB[linear pair]
PCB = 180-a

Now in triangle APE
x + a + 40 = 180
x = 180 - 40- a
x= 140 -a
again in triangle PCD
x + 180-a + 36 = 180
140 - a + 180 - a + 36 = 180
2a = 140 + 36
2a = 176
a= 88

Now x = 140-a = 140 - 88= 52
_____________________________

when y + z = 90
then
in triangle APE
a = 180-z- x---------1)

in triangle PCD
PCD = 180- PDC - CPD
180-a = 180 - y - x
a = x + y----------2)

Now comparing 1) and 2)
180 -z -x = x + y
x + x + y + z = 180
2x + 90 = 180
2x = 90
x = 1/2 x 90
x = 1/2 right angle

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how to solve this:- It is a 5 mark question i am offering you with 48 points for this questionanswer it in full steps pls answer fast

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how to solve this:-
It is a 5 mark question i am offering you with 48 points for this question
answer it in full steps
pls answer fast