how to solve this:-
It is a 5 mark question i am offering you with 48 points for this question
answer it in full steps
pls answer fast
Attachments:
Rabie:
please answer fast
no body knows the ans
ok
pls do it fast
Answers
Answered by
1
This is the answer. Hope this help. Mark as brainliest if it's good.
Attachments:
see picture is not opening, loading so I tell u the rest solution here
how to find exterior angle of triangle aep and pic, den see abcp is cyclc quad, den x+y+z+x=180,den x=52
z+y=90,from equation (2x+z+y=180),put value y+z=90, den x=45
sorry but picture is black when full screened.. so.. u do it this way u will get the ans, and u can get help from the part that can be seen
thanks
Answered by
2
Now
let EAP = a
PCB = a
[APCB is cyclic quadrilateral so exterior angle is equal to the interior opposite angle]
PCD = 180- PCB[linear pair]
PCB = 180-a
Now in triangle APE
x + a + 40 = 180
x = 180 - 40- a
x= 140 -a
again in triangle PCD
x + 180-a + 36 = 180
140 - a + 180 - a + 36 = 180
2a = 140 + 36
2a = 176
a= 88
Now x = 140-a = 140 - 88= 52
_____________________________
when y + z = 90
then
in triangle APE
a = 180-z- x---------1)
in triangle PCD
PCD = 180- PDC - CPD
180-a = 180 - y - x
a = x + y----------2)
Now comparing 1) and 2)
180 -z -x = x + y
x + x + y + z = 180
2x + 90 = 180
2x = 90
x = 1/2 x 90
x = 1/2 right angle
let EAP = a
PCB = a
[APCB is cyclic quadrilateral so exterior angle is equal to the interior opposite angle]
PCD = 180- PCB[linear pair]
PCB = 180-a
Now in triangle APE
x + a + 40 = 180
x = 180 - 40- a
x= 140 -a
again in triangle PCD
x + 180-a + 36 = 180
140 - a + 180 - a + 36 = 180
2a = 140 + 36
2a = 176
a= 88
Now x = 140-a = 140 - 88= 52
_____________________________
when y + z = 90
then
in triangle APE
a = 180-z- x---------1)
in triangle PCD
PCD = 180- PDC - CPD
180-a = 180 - y - x
a = x + y----------2)
Now comparing 1) and 2)
180 -z -x = x + y
x + x + y + z = 180
2x + 90 = 180
2x = 90
x = 1/2 x 90
x = 1/2 right angle
Similar questions