how to solve this please tell me
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Heya,
tan A= 15/8=perpendicular/base
sinA=perpendicular/hypotenuse
cosA=Base/hypotenuse
By Pythagoras theorem:-
(H)²=(P)²+(B)²
(H)²=(15)²+(8)²
(H)²=225+64
(H)²=289
H=17
sinA=15/17
cosA=8/17
Therefore,
sinA-cosA
=15/17-8/17
=15-8/17
= 7/17 ANSWER..
HOPE IT HELPS:-))
tan A= 15/8=perpendicular/base
sinA=perpendicular/hypotenuse
cosA=Base/hypotenuse
By Pythagoras theorem:-
(H)²=(P)²+(B)²
(H)²=(15)²+(8)²
(H)²=225+64
(H)²=289
H=17
sinA=15/17
cosA=8/17
Therefore,
sinA-cosA
=15/17-8/17
=15-8/17
= 7/17 ANSWER..
HOPE IT HELPS:-))
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