Question

how to solve this plz help.

Answer 1

$\frac{1}{9} \times{3}^{1002}$
$= {3}^{ - 2} \times {3}^{1002}$
by laws of exponentials
$= {3}^{1000}$

It can't be expressed further by normal calculation..
Hope this helps.
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Answer 2

pls mark as brainliest
$=3^{1002}$×1/9
9 can be written as 3²
∴$=3^{1002}$×1/3²
=3^1002/3^2
according to laws of exponents a^m/a^n=a^m-n
=3^1002-2=3^1000