Question

how to solve this problems ​

Answer 1

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$<b>Let n be the number of Terms</b>$

$\sf Here,First\:Term (a)=41 \\ \\ \sf Common\:difference(d)=41-38=3 \\ \\ \sf and\:last\:term (l)=8 \\ \\ \sf Now,l=a+(n-1)d \\ \\ \sf \implies 8=41+(n-1)3 \\ \\ \sf \implies 8=41+3n-3 \\ \\ \sf \implies 8+3-41=3n \\ \\ \sf \implies 30=3n \\ \\ \sf \implies n=10 \\ \\ \sf Hence,Number\:of\:terms=10$

❤hope it helps you ❤

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