Question

how to solve this question?​

Answer 1

Answer:

Step-by-step explanation:

as it is it will satisfy the equation

x-1=0

x=1

2x^3+ax^2+bx-6=0

a+b=4

when we put x=2 the value of expression is 2

16+4a+2b-6=2

4a-2b=-8

2a+b=-4

solving both equations we get

a=-8 b=12

Answer 2

Answer:

$p(x) = 2 {x}^{3} + a {x}^{2} + bx - 6 \\ (x - 1)is \: a \: factor \\ p(1) = 0 \\ 2 + a + b - 6 = 0 \\ a + b = 4.......eqn1 \\ p(2) = 2 \\ 2( {2}^{3} ) + a( {2}^{2} ) + 2b - 6 = 2 \\ 16 + 4a + 2b - 6 = 2 \\ 4a + 2b = - 8 .....eq2 \\ solving \: 1and2 \\ a = - 8 \\ b = 12$