Question

how to solve this question..​

Answer 1

Step-by-step explanation:

Given,

AC=DE

AB = EF

<ABC=<DFE

Consider triangle ABC and TRIANGLE DFE

AE=de

ab=ef

angle ABC=angle DFE

So, by RHS rule triangle ABC CONGRUENT To TRIANGLE DFE.

• ANGLE ACB =ANGLE CDE(cpct )
• Thus, AC ||DE(alternate interior angles of ab and de are equal
• angle ABC=angle BFE =90

180-angle ABC=angle ABD(linear pair )

180-90=angle ABD

• Angle ABD =90