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Answer: AB be 5 cm and CD be 11 cm

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circle

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circleAB = 6CM

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circleAB = 6CM OD = 3cm

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circleAB = 6CM OD = 3cm CD = 11 cm

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circleAB = 6CM OD = 3cm CD = 11 cmCD = 5.5 cm

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circleAB = 6CM OD = 3cm CD = 11 cmCD = 5.5 cmIn triangle ODC by Pythagoras therom

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circleAB = 6CM OD = 3cm CD = 11 cmCD = 5.5 cmIn triangle ODC by Pythagoras therom OC2 = OD2 + DC2

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circleAB = 6CM OD = 3cm CD = 11 cmCD = 5.5 cmIn triangle ODC by Pythagoras therom OC2 = OD2 + DC2 = 3 ×3 + 5.5 ×5.5

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circleAB = 6CM OD = 3cm CD = 11 cmCD = 5.5 cmIn triangle ODC by Pythagoras therom OC2 = OD2 + DC2 = 3 ×3 + 5.5 ×5.5 = 9 + 30.25

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circleAB = 6CM OD = 3cm CD = 11 cmCD = 5.5 cmIn triangle ODC by Pythagoras therom OC2 = OD2 + DC2 = 3 ×3 + 5.5 ×5.5 = 9 + 30.25 = 39.25

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circleAB = 6CM OD = 3cm CD = 11 cmCD = 5.5 cmIn triangle ODC by Pythagoras therom OC2 = OD2 + DC2 = 3 ×3 + 5.5 ×5.5 = 9 + 30.25 = 39.25 = √ 39.25

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circleAB = 6CM OD = 3cm CD = 11 cmCD = 5.5 cmIn triangle ODC by Pythagoras therom OC2 = OD2 + DC2 = 3 ×3 + 5.5 ×5.5 = 9 + 30.25 = 39.25 = √ 39.25 = 6.25 cm

Answer: AB be 5 cm and CD be 11 cm draw a line perpendicular to both AB and CD Draw OC which will be radius of the circleAB = 6CM OD = 3cm CD = 11 cmCD = 5.5 cmIn triangle ODC by Pythagoras therom OC2 = OD2 + DC2 = 3 ×3 + 5.5 ×5.5 = 9 + 30.25 = 39.25 = √ 39.25 = 6.25 cm therefore, the radius of the circle is 6.25 cm