Question

how to solve this question?

Answer 1

sol: Given AB=AC

→angleA + angleE + angleD = 180*(sum of the angle in a triangle is 180*)
→ ▲A+ 40*+ 45* = 180*
→ ▲A +85*= 180*
→ ▲A=180*- 85*
→ ▲A=95*-36*=59*
→ ▲ABC= ▲B=▲C=x(says)
→ 36*+x+x=180*
2x=180*-36*
2x =144*
x=144/2=72*
→▲DBA+▲ABC=180*
→▲DBA+72*=180*
→▲DBA=180*-72*=180*
→▲ADB+▲DBA+▲DAB=180*
→45*+105*+x=180*
153*+x=180*
x=180*-153*
x=27*
→▲ACB+▲ACE=180*
72*+x=180*
x=180*-72*=108*
→▲ACE+▲AEC+CAE=180*( sum of the angle in a traingle is supplementary)
108*+40*+x=180*
x*=180*-148*
x=32*
hope this help u :-)
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