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Since cos (90-theta)= sin theta, sin(90-theta)=cos theta
Sec theta =cosec(90-theta)
Cosec theta= sec(90- theta)
Therefore on putting values we get
Sin theta. cos theta . sin theta .sin theta .cos theta/cosec theta. Cos theta .cos theta.sin theta/sec thet . - 2cos theta sin theta
Sec theta =cosec(90-theta)
Cosec theta= sec(90- theta)
Therefore on putting values we get
Sin theta. cos theta . sin theta .sin theta .cos theta/cosec theta. Cos theta .cos theta.sin theta/sec thet . - 2cos theta sin theta
adityakute1817:
Sorry by mistakenly solved it only halfly
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