Question

how to solve this question

Answer 1

Join OP, draw OL ⟂ AB and OM ⟂ CD, thus, L and M are  the mid - points of AB and CD respectively. Also, equal chords are equidistant from the centre . 

∴ OL = OM 

Now, in right - angled △s OLP and OMP     

OL = OM 

OP = OP [common]

∠OLP = ∠OMP [each = 90°]

So, by RHS congruence axiom, we have 

△OLP ≅  △OMP 

Hence, ∠OLP = ∠OMP   [c.p.c.t.]